趣味的数学-379
若直线x+y=√(2m)是
圆x^2 + y^2 = m
的切线，
求m。
都是神算子！
Let (x,y) be the intersecting point of the circle and the tangent line,
Then, x+y = \sqrt(2m); x^2 + y^2 = m
x^2 + (\sqrt(2m)-x)^2 = m
Solve for x and y:
x= \sqrt(2m)/2
y= \sqrt(2m)/2
m can be any positive number.
