
The area of Triangle BED = 12. Proof: The area of Triangle ABC = 1/2 |AB| h = |MB| h = 24, hence h = 24/|MB| ........... (1) The area of Triangle CBE = 1/2 |EB| h = 1/2 |EC|*|BC| .......(2) Subtitute (1) into (2), we obtain : |EB| * 24/|MB| = |EC|*|BC| ............. (3) Triangles ECB and MDB are similar, hence |EB|/|MB| = |BC|/|BD| ......................(4) Subtitute (4) into (3), we obtain : |BC| * 24/|BD| = |EC|*|BC| , or 24 = |EC|*|BD| ............................... (5) On the other hand, we would like to have the area of Triangle BED, which is the difference of the area BEC and the area of DEC. The area of BEC is 1/2 |EC|*|BC|, and the area of DEC is 1/2 |EC|*|CD| , hence their difference is 1/2 |EC|*(|BC| - |CD|) = 1/2 |EC|* |BD|. By (5), this is 1/2 * 24 = 12 . 这是初等平面几何,俺会做的。 |